awk or perl one-liner to print line if second field is longer than 7 chars

Question

I have a file of 1000 lines, each line has 2 words, separated by a space. How can I print each line only if the last word length is greater than 7 chars? Can I use awk RLE

Answer 1

You can do:

perl -ne '@a=split/\s+/; print if length($a[1]) > 7' input_file.txt

Options used:

    -n  assume 'while () { ... }' loop around program
    -e  'command'    one line of program (several -e's allowed, omit programfile)

You can use the auto-split option as used by Chris

    -a  autosplit mode with -n or -p (splits $_ into @F)