awk or perl one-liner to print line if second field is longer than 7 chars

Question

I have a file of 1000 lines, each line has 2 words, separated by a space. How can I print each line only if the last word length is greater than 7 chars? Can I use awk RLE

Answer 1

@OP, awk's RLENGTH is used when you call match() function. Instead, use the length() function to check for length of characters

awk 'length($2)>7' file

if you are using bash, a shell solution

while read -r a b
do
  if [ "${#b}" -gt 7 ];then
    echo $a $b
  fi
done <"file"