I\'m using a function from this question, however, it doesn\'t seem to work in my case.
Basically, this script is going through a column selecting distinct values an
Short answer to your "Subscript out of range" error on the call of IsInArray function" question is that the variable arr is dimmed as Variant. For the Filter function to work in the IsInArray UDF arr must be dimmed as a String.
You can try the following code which 1) Sets up a filtered String array, and 2) avoids placing Redim Preserve (which is a costly function) in a loop:
Sub FilteredValuesInArray()
'http://stackoverflow.com/questions/16027095/checking-if-value-present-in-array
Dim rng As Range
Dim arrOriginal() As Variant, arrFilteredValues() As String
Dim arrTemp() As String
Dim strPrintMsg As String 'For debugging
Dim i As Long, lCounter As Long
Set rng = Cells(1, 1).CurrentRegion 'You can adjust this how you want
arrOriginal = rng
'Convert variant array to string array
ReDim arrTemp(LBound(arrOriginal) - 1 To UBound(arrOriginal) - 1)
For i = LBound(arrOriginal) To UBound(arrOriginal)
arrTemp(i - 1) = CStr(arrOriginal(i, 1))
Next i
'Setup filtered values array
ReDim arrFilteredValues(LBound(arrTemp) To UBound(arrTemp))
On Error Resume Next
Do
arrFilteredValues(lCounter) = arrTemp(0)
'Save non matching values to temporary array
arrTemp = Filter(arrTemp, arrTemp(0), False)
'If error all unique values found; exit loop
If Err.Number <> 0 Then Exit Do
lCounter = lCounter + 1
Loop Until lCounter >= UBound(arrFilteredValues)
On Error GoTo 0
'Resize array to proper bounds
ReDim Preserve arrFilteredValues(LBound(arrFilteredValues) To lCounter - 1)
'====DEBUG CODE
For i = LBound(arrFilteredValues) To UBound(arrFilteredValues)
strPrintMsg = strPrintMsg & arrFilteredValues(i) & vbCrLf
Next i
Debug.Print vbTab & "Filtered values are:" & vbCrLf & strPrintMsg
'====END DEBUG CODE
End Sub