Char arrays and scanf function in C

Question

I expected to get errors in following code, but I did not. I did not use & sign. Also I am editing array of chars.

#include <         


        

Answer 1

When you pass arrays to functions in C, they decay to pointers to the first item.

Therefore for:

char name[] ="yasser";

scanf("%s", name) is the same as scanf("%s", &name[0]) and either of those invocations should send shivers down your spine, because unless you control what's on your stdin (which you usually don't), you're reading a potentially very long string into a limited buffer, which is a segmentation fault waiting to happen (or worse, undefined behavior).