How to dynamically modify a function's local namespace?

Question

NB: This question assumes Python 2.7.3.

I\'m looking for a sane approach to dynamically modify a function\'s local namespace, preferably in a way that adds the lea

Answer 1

May be something like that

def foo():
    print(x)

foo.__globals__["x"] = "Hello Python"

foo()

unfortunately this does not works in body of function if varible has been defined

def foo(flag):
    x = "Hello World"
    if flag:
        foo.__globals__["x"] = "Hello Python"

    print(x)

prints Hello World in both flag is True or False