how to change date-format in a log file using bash, avoiding while loop

Question

This is not a new question here and here, but the details make it differ.

My input log file looks like:

TEMP MON -=- Sat Aug 15 02:20:24 EEST 2020 -=-          


        

Answer 1

You may use this awk solution:

awk 'BEGIN {
   FS=OFS=" -=- "
}
{
   cmd = sprintf("TZ=EET date -d \"%s\" +\"%Y-%m-%%d_%T %Z\"", $2);
   if ((cmd | getline output) > 0)
      $2 = output
   close(cmd)
} 1' file

TEMP MON -=- 2020-08-15_02:20:24 EEST -=- 48.6
TEMP MON -=- 2020-08-15_02:20:50 EEST -=- 49.1
TEMP MON -=- 2020-08-15_02:21:13 EEST -=- 49.1
TEMP MON -=- 2020-08-15_02:21:44 EEST -=- 49.1
TEMP MON -=- 2020-08-15_02:21:45 EEST -=- 48.6
TEMP MON -=- 2020-08-15_02:21:52 EEST -=- 49.1
TEMP MON -=- 2020-08-15_02:21:53 EEST -=- 48.6
TEMP MON -=- 2020-08-15_02:21:54 EEST -=- 49.6
TEMP MON -=- 2020-08-15_02:21:56 EEST -=- 49.1
TEMP MON -=- 2020-08-15_02:21:57 EEST -=- 49.1