I want to ignore square brackets when using javascript regex

Question

I am using javascript regex to do some data validation and specify the characters that i want to accept (I want to accept any alphanumeric characters, spaces and the followi

Answer 1

Try this: var pattern = /[^\w"!&,'\\-]/;

Note: \w also includes _, so if you want to avoid that then try

var pattern = /[^a-z0-9"!&,'\\-]/i;

I think the issue with your regex is that A-z is being understood as all characters between 0x41 (65) and 0x7A (122), which included the characters []^_` that are between A-Z and a-z. (Z is 0x5A (90) and a is 0x61 (97), which means the preceding characters take up 0x5B thru 0x60).