Exception not caught in try catch block

Question

I do a simple throw \"TEST THROW\" and it isn\'t caught in my catch (std::exception& e). Is it because I\'m catching an std::exception& e?

Answer 1

Another reason people may hit this issue, especially if they've been writing Java recently, is that they may be throwing a pointer to the exception.

/* WARNING WARNING THIS CODE IS WRONG DO NOT COPY */
try {
    throw new std::runtime_error("catch me");
} catch (std::runtime_error &err) {
    std::cerr << "exception caught and ignored: " << err.what() << std::end;
}
/* WARNING WARNING THIS CODE IS WRONG DO NOT COPY */

will not catch the std::runtime_error* you threw. It'll probably die with a call to std::terminate for the uncaught exception.

Don't allocate the exception with new, just throw the constructor by-value, e.g.

try {
    /* note: no 'new' here */
    throw std::runtime_error("catch me");
} catch (std::runtime_error &err) {
    std::cerr << "exception caught and ignored: " << err.what() << std::end;
}