Displaying the data dynamically using Ajax

Question

In this code, after clicking the like button, the data is added in the database already. What I wanted to do now is I would like after adding the data, I will query the tota

Answer 1

public function like_total(){
$data = array('like' => 1,
                'userID'=>$this->session->userdata('userID'),
                'uploadID'=>$_GET['like_id']);

$no_likes = $this->photoCheese_model->get_like_total($data,$this->input->get('like_id'));

$result['no_likes'] = $no_likes;

 $this->output->set_content_type('application/json')->set_output(json_encode($result)); 
}




    public function get_like_total($data,$this->input->get('like_id')){
    $success = $this->db->insert('tbl_like',$data);

    if($success){
    $this->db->select('SUM(`like`) as no_likes');
    $this->db->where('uploadID',$this->input->get('like_id'));            

    $query = $this->db->get('tbl_like');

    $res = $query->row_array();

    return $res['no_likes'];
    }

    return 0;
    }