Displaying the data dynamically using Ajax

Question

In this code, after clicking the like button, the data is added in the database already. What I wanted to do now is I would like after adding the data, I will query the tota

Answer 1

Try this.

public function like_total(){
    $id = $this->session->userdata('userID');
    $upload = $this->input->get('like_id');
    $data = array('like' => 1,
                    'userID'=>$id,
                    'uploadID'=>$_GET['like_id']);

    $no_likes = $this->photoCheese_model->get_like_total($data,$upload);

    $result['no_likes'] = $no_likes;

    $this->output->set_content_type('application/json')->set_output(json_encode($result)); 
}




public function get_like_total($data,$uplaod){
    $success = $this->db->insert('tbl_like',$data);

    if($success){
        $this->db->select('SUM(`like`) as no_likes');
        $this->db->where('uploadID',$upload);            

        $query = $this->db->get('tbl_like');

        $res = $query->row_array();

        return $res['no_likes'];
    }

    return 0;
}