Swift comparing Strings optionals vs non-optional

Question

When comparing strings in Swift, you can compare non-optional strings with optional strings.

Like so (text is an optional, and it is empty):

UITextF         


        

Answer 1

Your theory doesn’t hold in the following example:

let x: String? = nil

if x == "" {
    print("True")
} else {
    print("False") //Printed
}

What’s actually happening here is that the text property is never actually nil upon initialisation — it is instead an empty string, as given by the documentation:

This string is @"" by default.

The Swift compiler does not implicitly unwrap any optionals, it instead leaves that responsibility to the programmer.