The following code compiles fine. However I wonder if it is legal C++. So more specific, if I have a const object, am I allowed to modify variables through pointers/referenc
It's legal, as const-ness of the class means that the class member is constant. a
is a pointer, so the address the pointer points to is constant, but the value stored at that address need not be.
Hence bar.a
is effectively an int * const
, not an int const *
.
As, after initialization, a reference cannot be made to refer to another entity anyway, it does not matter for bar.b
whether bar
is declared const
or not.
The constant variant of a pointer is a constant pointer, not a pointer to a constant. The constant variant of a reference is a reference, not a reference to a constant.
Small digression: You should be careful with references as members anyway in connection with const-ness, as the following will probably compile
struct Y { int m_a; };
struct X {
const Y & m_y;
X (const Y & y) : m_y (y) { }
};
Y y;
y.m_a = 1;
X x (y); // or const X x (y) -- does not matter
// X.m_y.m_a == 1
y.m_a = 2;
// now X.m_y.m_a == 2, although X.m_y is supposed to be const
As it is possible to assign a pointer to non-const to a pointer to const, you can build an analogous example with pointers. Remember that const
does only guarantee that YOU will not modify a variable via this very variable, it cannot guarantee that the contents of the variable are not modified at all.