Switch statement using string on an array

Question

#include

int main(){

    char name[20];

    printf(\"enter a name \");
    scanf(\"%s\",name);
    switch(name[20]){
        case \"kevin\" : 
             


        

Answer 1

There are plenty of ways to go about this! For example, use a...

3-letter hash

#include 

int main(){

    char name[20];

    printf("enter a name ");
    scanf("%s",name);
    switch((int)*name * (int)*(name+1) * (int)*(name+2)){
          case (1275226) : // "kevin"
            printf("hello %s.\n", name);
            break;
          case (1293980) : // "astro"
            printf("welcome %s.\n", name);
            break;
    }
    printf("%d",(int)*name * (int)*(name+1) * (int)*(name+2));
}