Finding if any element in a list is in another list and return the first element found

Question

It is easy to check if an element of a list is in another list using any():

any(elem in list2 for elem in list1)

but is there

Answer 1

Use a list comprehension:

[elem for elem in list1 if elem in list2]

Example:

list1 = [1, 2, 3, 4, 5]
list2 = [1, 10, 2, 20]

c = [elem for elem in list1 if elem in list2]
print(c)

Output

[1, 2]