Finding if any element in a list is in another list and return the first element found

Question

It is easy to check if an element of a list is in another list using any():

any(elem in list2 for elem in list1)

but is there

Answer 1

Yes, it is possible, by using a filter when doing your list comprehension :

list1 = ['a', 'b', 'c', 'd', 'e']
list2 = ['g', 'z', 'b', 'd', '33']
[elem for elem in list1 if elem in list2]
# ['b', 'd']