Bash script: always show menu after loop execution

Question

I\'m using a bash script menu like this:

#!/bin/bash
PS3=\'Please enter your choice: \'
options=(\"Option 1\" \"Option 2\" \"Option3\" \"Quit\")
select opt i         


        

Answer 1

You can also do something like:

#!/bin/bash

PS3='Please enter your choice: '
options=("Option 1" "Option 2" "Option 3" "Quit")
select opt in "${options[@]}"
do
    case $opt in
        "Option 1")
            echo "you chose choice 1"
            ;;
        "Option 2")
            echo "you chose choice 2"
            ;;
        "Option 3")
            echo "you chose choice 3"
            ;;
        "Quit")
            break
            ;;
        *) echo invalid option;;
    esac
    counter=1
    SAVEIFS=$IFS
    IFS=$(echo -en "\n\b")   # we set another delimiter, see also: https://www.cyberciti.biz/tips/handling-filenames-with-spaces-in-bash.html
    for i in ${options[@]};
    do
        echo $counter')' $i
        let 'counter+=1'
    done
    IFS=$SAVEIFS
done