how to calculate percent of total within group by statement?

Question

I have a table with 1 record per sale per salesperson per day

NAME  DATE
joe   1-1-13
joe   1-1-13
joe   1-1-13
dave  1-1-13
joe   1-2-13

I

Answer 1

Not the most elegant way to do it, but you can try this -

select [name],[salesdate], COUNT(*) as dayTotal, 
SUM(COUNT(*)) over() as AllSales, 
(COUNT(*) * 1.0) / SUM(COUNT(*)) over() as dayPercent
FROM [dbo].[sales]
group by [name], [salesdate]

I removed the # in your table name. Btw, this code depends on OVER() clause. You can find out how to truncate the excess zeros yourself.

name    salesdate   dayTotal    AllSales    dayPercent
dave    2013-01-01  1           5           0.200000000000
joe   2013-01-01    3           5           0.600000000000
joe   2013-01-02    1           5           0.200000000000

HTH.

If that query looks too complicated to you, then look at this one first. It will give you an idea of what I am trying to do.

select [name],[salesdate], COUNT(*) as dayTotal, 
SUM(COUNT(*)) over() as AllSales
FROM [dbo].[sales]
group by [name], [salesdate]