what is the purpose of putting a space in scanf like this scanf(“ %c”,&ch) in place of scanf(“%c”,&ch)? [duplicate]

Answer 1

I had the same problem a while ago in which if I would try to read a variable using scanf ("%c", &ans); it would not read anything. Thus I figured out that the \n character from the last input was being read.

Thus, doing scanf (" %c", &ans); solved my problem.

Although, I could not understand your second question clearly.