How to remove scheme from url in Python?

Question

I am working with an application that returns urls, written with Flask. I want the URL displayed to the user to be as clean as possible so I want t

Answer 1

I don't think urlparse offers a single method or function for this. This is how I'd do it:

from urlparse import urlparse

url = 'HtTp://stackoverflow.com/questions/tagged/python?page=2'

def strip_scheme(url):
    parsed = urlparse(url)
    scheme = "%s://" % parsed.scheme
    return parsed.geturl().replace(scheme, '', 1)

print strip_scheme(url)

Output:

stackoverflow.com/questions/tagged/python?page=2

If you'd use (only) simple string parsing, you'd have to deal with http[s], and possibly other schemes yourself. Also, this handles weird casing of the scheme.