Does the using statement dispose only the first variable it create?

Question

Let\'s say I have a disposable object MyDisposable whom take as a constructor parameter another disposable object.

using(MyDisposable myDisposab         


        

Answer 1

In this case, it won't dispose the AnotherDisposable. There are two solutions to this.

First, what you would normally do is the following:

using (AnotherDisposable anotherDisposable = new AnotherDisposable())
using (MyDisposable myDisposable= new MyDisposable(anotherDisposable))
{
}

However, there is a different way to go. It's normal that when a class takes a disposable, it itself will take care of disposing the object it took. E.g. the StreamReader that wraps a Stream will dispose of the Stream it wraps. That means that the construct you choose would work. You can implement this same feature in MyDisposable and then the approach you took will be OK.