Efficient retrieval of releases that contain a commit

Question

In the command line, if I type

git tag --contains {commit}

to obtain a list of releases that cont

Answer 1

You can get this almost directly from git rev-list.

latest.awk:

BEGIN { thiscommit=""; }
$1 == "commit" {
    if ( thiscommit != "" )
        print thiscommit, tags[thiscommit]
    thiscommit=$2
    line[$2]=NR
    latest = 0;
    for ( i = 3 ; i <= NF ; ++i ) if ( line[$i] > latest ) {
        latest = line[$i];
        tags[$2] = tags[$i];
    }
    next;
}
$1 != "commit"  { tags[thiscommit] = $0; }
END { if ( thiscommit != "" ) print thiscommit, tags[thiscommit]; }

a sample command:

git rev-list --date-order --children --format=%d --all | awk -f latest.awk

you can also use --topo-order, and you'll probably have to weed out unwanted refs in the $1!="commit" logic.

Depending on what kind of transitivity you want and how explicit the listing has to be, accumulating the tags might need a dictionary. Here's one that gets an explicit listing of all refs for all commits:

all.awk:

BEGIN {
    thiscommit="";
}
$1 == "commit" {
    if ( thiscommit != "" )
        print thiscommit, tags[thiscommit]
    thiscommit=$2
    line[$2]=NR
    split("",seen);
    for ( i = 3 ; i <= NF ; ++i ) {
        nnew=split(tags[$i],new);
        for ( n = 1 ; n <= nnew ; ++n ) {
            if ( !seen[new[n]] ) {
                tags[$2]= tags[$2]" "new[n]
                seen[new[n]] = 1
            }
        }
    }
    next;
}
$1 != "commit"  {
    nnew=split($0,new,", ");
    new[1]=substr(new[1],3);
    new[nnew]=substr(new[nnew],1,length(new[nnew])-1);
    for ( n = 1; n <= nnew ; ++n )
        tags[thiscommit] = tags[thiscommit]" "new[n]

}
END { if ( thiscommit != "" ) print thiscommit, tags[thiscommit]; }

all.awk took a few minutes to do the 322K linux kernel repo commits, about a thousand a second or something like that (lots of duplicate strings and redundant processing) so you'd probably want to rewrite that in C++ if you're really after the complete cross-product ... but I don't think gitk shows that, only the nearest neighbors, right?