Php 404 Not Found Header

Question

I am trying to understand the combination of 3 simple php code lines, This is the code:

ob_end_clean();
header(\'HTTP/1.0 404 Not Found\');
exit;
         


        

Answer 1

If i remove the first line and i got a BOM at the document i get blank page (No 404). you get blank 404 because you have no content defined in there...

header('HTTP/1.0 404 Not Found');

is only giving notice that user is on 404 error page site... if you want to display some 404 notice for user you can do this by loading your 404.html file

if(strstr($_SERVER['REQUEST_URI'],'index.php')){
  header('HTTP/1.0 404 Not Found');
  readfile('404missing.html');
  exit();
}

or directly

if (strstr($_SERVER['REQUEST_URI'],'index.php')){
    header('HTTP/1.0 404 Not Found');
    echo "
Error 404 Not Found
";
    echo "The page that you have requested could not be found.";
    exit();
}

exit function is there because you have to prevent execution of another php code, which may be directly after if or which may be excecuted later, simply it says END