i have the following mysql database table designed,
ticket(id, code, cust_name);
passenger(id, ticket_id, name, age, gender, fare);
service(id, passenger_id,
First of all in your current table schema you have no way to distinguish between services that have been sold to the same passenger in different tickets. Therefore you have no way to correctly calculate total_cost
per ticket. You have to have ticket_id
in your service
table.
Now, if you were to have a ticket_id
in service
table then a solution with a correlated subqueries might look like
SELECT t.*,
(SELECT SUM(fare)
FROM passenger
WHERE ticket_id = t.id) total_fare,
(SELECT SUM(cost)
FROM service
WHERE ticket_id = t.id) total_cost
FROM ticket t
or with JOIN
s
SELECT t.id,
p.fare total_fare,
s.cost total_cost
FROM ticket t LEFT JOIN
(
SELECT ticket_id, SUM(fare) fare
FROM passenger
GROUP BY ticket_id
) p
ON t.id = p.ticket_id LEFT JOIN
(
SELECT ticket_id, SUM(cost) cost
FROM service
GROUP BY ticket_id
) s
ON t.id = s.ticket_id
Note: Both queries take care of the fact that passenger can have multiple services per ticket or no services at all.
Now with your current schema
SELECT t.*,
(SELECT SUM(fare)
FROM passenger
WHERE ticket_id = t.id) total_fare,
(SELECT SUM(cost)
FROM service s JOIN passenger p
ON s.passenger_id = p.id
WHERE p.ticket_id = t.id) total_cost
FROM ticket t
and
SELECT t.id,
p.fare total_fare,
s.cost total_cost
FROM ticket t LEFT JOIN
(
SELECT ticket_id, SUM(fare) fare
FROM passenger
GROUP BY ticket_id
) p
ON t.id = p.ticket_id LEFT JOIN
(
SELECT p.ticket_id, SUM(cost) cost
FROM service s JOIN passenger p
ON s.passenger_id = p.id
GROUP BY p.ticket_id
) s
ON t.id = s.ticket_id
SELECT t.*,
(SELECT SUM(fare)
FROM passenger
WHERE ticket_id = t.id) +
(SELECT SUM(cost)
FROM service s JOIN passenger p
ON s.passenger_id = p.id
WHERE p.ticket_id = t.id) grand_total
FROM ticket t
or
SELECT t.id,
p.fare + s.cost grand_total
FROM ticket t LEFT JOIN
(
SELECT ticket_id, SUM(fare) fare
FROM passenger
GROUP BY ticket_id
) p
ON t.id = p.ticket_id LEFT JOIN
(
SELECT p.ticket_id, SUM(cost) cost
FROM service s JOIN passenger p
ON s.passenger_id = p.id
GROUP BY p.ticket_id
) s
ON t.id = s.ticket_id