SQL Server Join In Order

Question

I have 2 string in input for example \'1,5,6\' and \'2,89,9\' with same number of element (3 or plus). Those 2 string i want made a \"ordinate join\" as

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Answer 1

You can do it like this as well

Consider your split function like this:

CREATE FUNCTION Split
(
  @delimited nvarchar(max),
  @delimiter nvarchar(100)
) RETURNS @t TABLE
(
  id int identity(1,1),
  val nvarchar(max)
)
AS
BEGIN
  declare @xml xml
  set @xml = N'' + replace(@delimited,@delimiter,'') + ''

  insert into @t(val)
  select 
    r.value('.','varchar(5)') as item
  from @xml.nodes('//root/r') as records(r)

  RETURN
END
GO

The it will be a simple task to JOIN them together. Like this:

SELECT
    *
FROM
    dbo.Split('1,5,6',',') AS a
    JOIN dbo.Split('2,89,9',',') AS b
        ON a.id=b.id

The upside of this is that you do not need any ROW_NUMBER() OVER(ORDER BY SELECT 0)

Edit

As in the comment the performance is better with a recursive split function. So maybe something like this:

CREATE FUNCTION dbo.Split (@s varchar(512),@sep char(1))
RETURNS table
AS
RETURN (
    WITH Pieces(pn, start, stop) AS (
      SELECT 1, 1, CHARINDEX(@sep, @s)
      UNION ALL
      SELECT pn + 1, stop + 1, CHARINDEX(@sep, @s, stop + 1)
      FROM Pieces
      WHERE stop > 0
    )
    SELECT pn,
      SUBSTRING(@s, start, CASE WHEN stop > 0 THEN stop-start ELSE 512 END) AS s
    FROM Pieces
  )
GO

And then the select is like this:

SELECT
    *
FROM
    dbo.Split('1,5,6',',') AS a
    JOIN dbo.Split('2,89,9',',') AS b
        ON a.pn=b.pn