java regex quantifiers

后端 未结 6 2164
春和景丽
春和景丽 2021-01-12 08:00

I have a string like

String string = \"number0 foobar number1 foofoo number2 bar bar bar bar number3 foobar\";

I need a regex to give me th

6条回答
  •  自闭症患者
    2021-01-12 08:43

    So you want number (+ an integer) followed by anything until the next number (or end of string), right?

    Then you need to tell that to the regex engine:

    Pattern pattern = Pattern.compile("number\\d+(?:(?!number).)*");
    

    In your regex, the .* matched as much as it could - everything until the end of the string. Also, you made the second part (number\\d+)? part of the match itself.

    Explanation of my solution:

    number    # Match "number"
    \d+       # Match one of more digits
    (?:       # Match...
     (?!      #  (as long as we're not right at the start of the text
      number  #   "number"
     )        #  )
     .        # any character
    )*        # Repeat as needed.
    

提交回复
热议问题