I am having two arrays, how can i compare the two arrays at single shot.
var arr1= [\"a\",\"b\",\"c\"];
var arr2 = [\"a\",\"c\",\"d\"]
if(arr1 == a
var arr1 = ["a","b","c"];
var arr2 = ["a","c","d"];
if (arr1.length == arr2.length
&& arr1.every(function(u, i) {
return u === arr2[i];
})
) {
console.log(true);
} else {
console.log(false);
}
Side note for edge cases:
=== is often considered slightly broken for this kind of task because NaN behaves unexpectedly:
var arr1 = ["a",NaN,"b"];
var arr2 = ["a",NaN,"b"];
if (arr1.length == arr2.length
&& arr1.every(function(u, i) {
return u === arr2[i];
})
) {
console.log(true);
} else {
console.log(false);
}
The code above actually logs false because NaN !== NaN. In addition, === can't distinguish +0 from -0. To cover both of these cases, you could use a stronger comparison known as "egal" or "is", which can easily be implemented like so:
function is(a, b) {
return a === b && (a !== 0 || 1 / a === 1 / b) // false for +0 vs -0
|| a !== a && b !== b; // true for NaN vs NaN
}
var arr1 = ["a",NaN,"b"];
var arr2 = ["a",NaN,"b"];
if (arr1.length == arr2.length
&& arr1.every(function(u, i) {
// Use "is" instead of "==="
return is(u, arr2[i]);
})
) {
console.log(true);
} else {
console.log(false);
}