Unknown column issue with mysql alias

Question

I can\'t figure out why i am getting an unknown column when the column is an alias that was created. Any help would be great.

code:

SELECT DISTINCT 
         


        

Answer 1

I don't think you can use your "width" alias in your "width between .. and .."; you need to repeat the raw calculation, sadly. Same for "height". So, the following should work:

SELECT   DISTINCT c.id, 
         ((SUM(c.width_feet)*12)+(SUM(c.width_inches))) AS width, 
         ((SUM(c.height_feet)*12)+(SUM(c.height_inches))) AS height 
FROM     carpets AS c 
WHERE    c.active = '1' 
AND      (((SUM(c.width_feet)*12)+(SUM(c.width_inches))) BETWEEN '0' AND '275') 
AND      (((SUM(c.height_feet)*12)+(SUM(c.height_inches))) BETWEEN '0' AND '599') 
ORDER BY c.item_no