Python: Finding the last index of min element?

Question

For example [1,2,3,4,1,2]

has min element 1, but it occurs for the last time at index 4.

Answer 1

>>> from operator import itemgetter
>>> from itertools import izip,count
>>> min(izip(count(len(L)-1,-1), reversed(L)), key=itemgetter(1))[0]
4

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Explanation

reversed returns iterator which goes through original list without creating temporary list:

>>> reversed(L)

izip and count are lazy, and there seems to be no byte-code execution, so I expect this solution to be pretty fast, and one-liner at that.

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Time comparisons

http://ideone.com/ZQuge3

Solutions using index turned out to be fastest despite they have to make 2 passes over list. Other solutions create auxiliary tuples inside generators on each iteration and I think it is the reason why these solutions are slower. Even akson128's solution which invokes byte-code execution is still faster (because it doesn't have to create tuples).