Python: Finding the last index of min element?

Question

For example [1,2,3,4,1,2]

has min element 1, but it occurs for the last time at index 4.

Answer 1

a = [1,2,3,4,1,2]

a.reverse()
print len(a) - a.index(min(a)) - 1

Update after comment:

The side effect can be removed by reversing again (but of course that is quite inefficient).

a.reverse()