I hope this code explains the problem:
class Foo {
void a() { / *stuff */ }
}
class Bar extends Foo {
void a() { throw new Exception(\"This is not a
You can call any method from the outer class with Outer.this.method().
But methods are resolved at runtime, so if you have overridden it in your subclass, only the subclass method (Bar.a()) can access the original (by calling super.a()).
As you probably discovered, you can't write Bar.this.super.a() -- but even if you could, it would still give you Bar.a(), not Foo.a().