Reorder dictionary in python according to a list of values

Question

Let us consider a dictionary:

sample_dict={1:\'r099\',2:\'g444\',3:\'t555\',4:\'f444\',5:\'h666\'}

I want to re-order this dictionary in an

Answer 1

Answer for Python 3.6+

Guido has assured dictionaries would be ordered from Python 3.7 onwards, and they already were as an experimental feature in 3.6. The answer has already been expanded on in Fastest way to sort a python 3.7+ dictionary.

In this case, building a new dict with simple dictionary comprehension based on the items contained in the desired_order_list will do the trick.

sample_dict = {1: 'r099', 2: 'g444', 3: 't555', 4: 'f444', 5: 'h666'}
print(sample_dict)
>>> {1: 'r099', 2: 'g444', 3: 't555', 4: 'f444', 5: 'h666'}

desired_order_list = [5, 2, 4, 3, 1]

reordered_dict = {k: sample_dict[k] for k in desired_order_list}
print(reordered_dict)
>>> {5: 'h666', 2: 'g444', 4: 'f444', 3: 't555', 1: 'r099'}