boost::format with variadic template arguments

Question

Suppose I have a printf-like function (used for logging) utilizing perfect forwarding:

template
void awesome_printf         


        

Answer 1

Just to summarize the void.pointer's solution and the hints proposed by Praetorian, T.C. and Jarod42, let me provide the final version (online demo)

#include 
#include 

template
std::string FormatArgs(const std::string& fmt, const Arguments&... args)
{
    boost::format f(fmt);
    std::initializer_list {(static_cast(
        f % args
    ), char{}) ...};

    return boost::str(f);
}

int main()
{
    std::cout << FormatArgs("no args\n"); // "no args"
    std::cout << FormatArgs("%s; %s; %s;\n", 123, 4.3, "foo"); // 123; 4.3; foo;
    std::cout << FormatArgs("%2% %1% %2%\n", 1, 12); // 12 1 12
}

Also, as it was noted by T.C., using the fold expression syntax, available since C++17, the FormatArgs function can be rewritten in the more succinct way

template
std::string FormatArgs(const std::string& fmt, const Arguments&... args)
{
    return boost::str((boost::format(fmt) % ... % args));
}