split list into 2 lists corresponding to every other element

Question

I know there are many chunky ways to do this, but I am looking for a slick pythonic way to accomplish the following. Given a list of numbers:

a = [0,1,2,3,4,         


        

Answer 1

Try This :

a = [0,1,2,3,4,5,6,7,8,9]
>>> b=[i for x,i in enumerate(a) if x%2==1]
>>> c=[i for x,i in enumerate(a) if x%2==0]
>>> b
  [1, 3, 5, 7, 9]
>>> c
  [0, 2, 4, 6, 8]