.NET : How to validate XML file with DTD without DOCTYPE declaration

Question

I have an XML file with no DOCTYPE declaration that I would like to validate with an external DTD upon reading.

Dim x_set As Xml.XmlReaderSettings = New Xml.         


        

Answer 1

private static bool _isValid = true;
static void Main(string[] args)
{
    using (MemoryStream ms = new MemoryStream())
    {
        using (FileStream file = new FileStream("C:\\MyFolder\\Product.dtd", FileMode.Open, FileAccess.Read))
        {
            byte[] bytes = new byte[file.Length];
            file.Read(bytes, 0, (int) file.Length);
            ms.Write(bytes, 0, (int) file.Length);
        }
        using (FileStream file = new FileStream("C:\\MyFolder\\Product.xml", FileMode.Open, FileAccess.Read))
        {
            byte[] bytes = new byte[file.Length];
            file.Read(bytes, 0, (int) file.Length);
            ms.Write(bytes, 0, (int) file.Length);
        }
        ms.Position = 0;

        var settings = new XmlReaderSettings();
        settings.DtdProcessing = DtdProcessing.Parse;
        settings.ValidationType = ValidationType.DTD;
        settings.ValidationEventHandler += new ValidationEventHandler(OnValidationEvent);
        var reader = XmlReader.Create(ms, settings);

        // Parse the file.  
        while (reader.Read()) ;
    }
    // Check whether the document is valid or invalid.
    if (_isValid)
        Console.WriteLine("Document is valid");
    else
        Console.WriteLine("Document is invalid");
}

private static void OnValidationEvent(object obj, ValidationEventArgs args)
{
    _isValid = false;
    Console.WriteLine("Validation event\n" + args.Message);
}