Initializer list in user-defined literal parameter

Question

I don\'t know if it\'s possible but I want to do stuff like

int someval = 1;
if({1,2,3,4}_v.contains(someval ))

but when I try to define l

Answer 1

you'd expect syntax to be

if value in (value1, value2 ...) 

or something similar.

If you're willing to add one extra character, try this syntax:

#include 
#include 
#include 

template 
bool operator *(const T0& lhs, const std::array& rhs) {
  return std::find(begin(rhs), end(rhs), lhs) != end(rhs);
}

template std::array in(T0 arg0, T...args) {
  return {{arg0, args...}};
}

int main () {
  if( 2 *in(1,2,3) ) { std::cout << "Hello\n"; }
  if( 4 *in(5,6,7,8) ) { std::cout << "Goodbye\n"; }
}