What's the right way to parseFloat in Java

Question

I notice some issues with the Java float precision

       Float.parseFloat(\"0.0065\") - 0.001  // 0.0055000000134110451
       new Float(\"0.027\") - 0.001          


        

Answer 1

Floating point cannot accurately represent decimal numbers. If you need an accurate representation of a number in Java, you should use the java.math.BigDecimal class:

BigDecimal d = new BigDecimal("0.0065");