Partial function application prematurely runs codeblock when used with underscore

Question

Given:

def save(f: => Any)(run:Boolean) { if (run) { println(\"running f\"); f } else println(\"not running f\") } 

I can call it with:<

Answer 1

First case,

save(throw new RuntimeException("boom!")) _ 

According to "Scala Reference" (§6.7), trailing underscore is used in place of the argument list, and expression is converted to

val f: (Boolean) => Unit = save(throw new RuntimeException("boom!"))

where the first argument of def save is immediately evaluated.

The expression e _ is well-formed if e is of method type or if e is a call-by-name parameter. If e is a method with parameters, e _ represents e converted to a function type by eta expansion (§6.26.5). If e is a parameterless method or call-by-name parameter of type =>T , e _ represents the function of type () => T , which evaluates e when it is applied to the empty parameterlist ().

To make the things work as you expect, some modifications are required:

scala> def save(f:() => Any)(run:Boolean) { if (run) { println("running f"); f() } else println("not running f") }
save: (f: () => Any)(run: Boolean)Unit

scala> val f = save(() => throw new RuntimeException("boom!")) _
f: (Boolean) => Unit = 

scala> f(true)
running f
java.lang.RuntimeException: boom!
        at $anonfun$1.apply(:6)

Second case,

save(throw new RuntimeException("boom!"))(_)

According to "Scala Reference" (§6.23), when placeholder is used as a replacement for an argument, the expression is converted to

val f: (Boolean) => Unit = save(throw new RuntimeException("boom!"))(_)