How to find the permutation of a sort in Java

Question

I want to sort an array and find the index of each element in the sorted order. So for instance if I run this on the array:

[3,2,4]

I\'d ge

Answer 1

import java.io.*;

public class Sample {
    public static void main(String[] args) {
        int[] data = {0, 3, 2, 4, 6, 5, 10};//case:range 0 - 10
        int i, rangeHigh = 10;
        int [] rank = new int[rangeHigh + 1];
        //counting sort
        for(i=0; i< data.length ;++i) ++rank[data[i]];
        for(i=1; i< rank.length;++i) rank[i] += rank[i-1];
        for(i=0;i