Python regular expression to remove all square brackets and their contents

Question

I am trying to use this regular expression to remove all instances of square brackets (and everything in them) from strings. For example, this works when there is only one p

Answer 1

For Numbers inside the brackets (No Alphabets), e.g. [89], [23], [11], etc., this is the pattern to use.

import re

text = "The[TEXT] rain in[33] Spain[TEXT] falls[12] mainly in[23] the plain![45]"
pattern = "\[\d*?\]"
numBrackets = re.findall(pattern, text)

print(numBrackets)

Output:

['[33]', '[12]', '[23]', '[45]']