Protected member function address in derived class is not accessible

Question

#include 

class A {
protected:
    void foo()
    {}
};

class B : public A {
public:
    void bar()
    {
       std::cout << (&A::foo) &         


        

Answer 1

Seems I found the answer. If we could get pointer of member function we can call it for other objects of type A (not this) which is not allowed.

It is not allowed to call protected member function in derived classes for objects other than this. Getting pointer would violent that.

We can do something like this:

#include 

class A {
protected:
    void foo()
    {}
};

class B : public A {
public:
    void bar()
    {
        void (A::*fptr)() = &A::foo;

        A obj;
        (obj.*fptr)();

        // obj.foo(); //this is not compiled too.    
    }
};

int main()
{
    B b;
    b.bar();
}