Protected member function address in derived class is not accessible

Question

#include 

class A {
protected:
    void foo()
    {}
};

class B : public A {
public:
    void bar()
    {
       std::cout << (&A::foo) &         


        

Answer 1

I was curious and tried the following example:

#include 
using namespace std;

class A {
public:
    void foo()
    {
    }
};

class B : public A {
public:
    void bar()
    {
       printf("%p\n", (&A::foo));
       printf("%p\n", (&B::foo));
    }
};

int main()
{
    B b;
    b.bar();
}

Actually, I see that &A::foo == &B::foo, so for protected member of base class you can use derived class member to take address. I suppose in case of virtual functions this will not work