How to have sub-parser arguments in separate namespace with argparse?

Question

I have the following test-code

import argparse
parser = argparse.ArgumentParser()
parser.add_argument(\"--verbose\", default = 0, type=int)

subparsers = par         


        

Answer 1

You need to go into the bowels of argparse a bit but changing your script to the following should do the trick:

import argparse
from argparse import _HelpAction, _SubParsersAction

class MyArgumentParser(argparse.ArgumentParser):
    def parse_args(self, *args, **kw):
        res = argparse.ArgumentParser.parse_args(self, *args, **kw)
        from argparse import _HelpAction, _SubParsersAction
        for x in parser._subparsers._actions:
            if not isinstance(x, _SubParsersAction):
                continue
            v = x.choices[res.parser_name] # select the subparser name
            subparseargs = {}
            for x1 in v._optionals._actions: # loop over the actions
                if isinstance(x1, _HelpAction): # skip help
                    continue
                n = x1.dest
                if hasattr(res, n): # pop the argument
                    subparseargs[n] = getattr(res, n)
                    delattr(res, n)
            res.subparseargs = subparseargs
        return res

parser = MyArgumentParser()
parser.add_argument("--verbose", default = 0, type=int)

subparsers = parser.add_subparsers(dest = "parser_name")

parser_lan = subparsers.add_parser('car')
parser_lan.add_argument("--boo")
parser_lan.add_argument("--foo")

parser_serial = subparsers.add_parser('bus')
parser_serial.add_argument("--fun")

print parser.parse_args()