How to get url text out of field with HYPERLINK in it

Question

I have a column with hyperlinks formula in it, for example:

=HYPERLINK(\"http://example.com\", \"Link\")

I want to get additional column, w

Answer 1

Try this formulas

A2=index(SPLIT(SUBSTITUTE(FORMULATEXT(A1),"=HYPERLINK(""",""),""","""),1,1)

example

A1=HYPERLINK("http://example.com", "Link")

result is

A2=http://example.com