Does deleting void pointer guarantee to delete right size? [duplicate]

Answer 1

It is not necessary to use a smart pointer, it's just smart.

That being said, there are many other possibilities; the only thing to do is to store the type information along the actual object.

class Holder {
public:
    template 
    explicit Holder(T const volatile* t):
        _data(static_cast(t)),
        _delete(&Delete)
    {}

    void apply() { _deleter(_data); }

private:
    typedef void (*Deleter)(void const volatile*);

    template 
    static void Delete(void const volatile* p) {
        delete static_cast(p);
    }

    void const volatile* _data;
    Deleter _deleter;
};

And now:

std::list owningList;

owningList.push_back(Holder(somePointer));

for (Holder& h: owningList) { h.apply(); }