Regex for Discover credit card

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一整个雨季
一整个雨季 2021-01-11 15:43

I have read through this question, but for Discover card, the starting digits are 6011, 622126-622925, 644-649, 65 instead of just 6011, 65. (Sourc

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  •  误落风尘
    2021-01-11 16:13

    Here's your regex (demo):

    ^6(?:011\d{12}|5\d{14}|4[4-9]\d{13}|22(?:1(?:2[6-9]|[3-9]\d)|[2-8]\d{2}|9(?:[01]\d|2[0-5]))\d{10})$
    

    Needless to say, I won't exactly call this pretty or easy to maintain. I would recommend parsing the number as an integer and using your programming language to do the checks.

    You should also use Luhn algorithm to check if the credit card number is valid, and while you could theoretically do this with regex, it would many times worse than this.


    Allow me to show you how I arrived at this monstrosity, step by step. First, here is how you match each of those ranges:

    6011        # matches 6011
    65          # matches 65
    64[4-9]     # matches 644-649
    622(1(2[6-9]|[3-9]\d)|[2-8]\d{2}|9([01]\d|2[0-5]))  
                # matches 622126-622925
    

    Now, you want to match the rest of the digits:

    6011\d{12}        # matches 6011 + 12 digits
    65\d{14}          # matches 65 + 14 digits
    64[4-9]\d{13}     # matches 644-649 + 13 digits
    622(1(2[6-9]|[3-9]\d)|[2-8]\d{2}|9([01]\d|2[0-5]))\d{10}
                      # matches 622126-622925 + 10 digits
    

    Now you can combine all four, and add start and end of line anchors:

    ^(                  # match start of string and open group
     6011\d{12}|        # matches 6011 + 12 digits
     65\d{14}|          # matches 65 + 14 digits
     64[4-9]\d{13}|     # matches 644-649 + 13 digits
     622(1(2[6-9]|[3-9]\d)|[2-8]\d{2}|9([01]\d|2[0-5]))\d{10}
                        # matches 622126-622925 + 10 digits
    )$                  # close group and match end of string
    

    The final product above is a slightly compacted version of the previous regex, and I also made groups non-capturing (that's what those ?: are for).

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