C++ copy constructor invocation

Question

As far as i know, a copy constructor is invoked in the following scenarios :

1) Pass by value
2) Return by value
3) When you create and initialize a new obje         


        

Answer 1

When doing x = funct(); the compiler notices that it will be directly returned and thus avoids a useless construction. That's also why you will only get two destructor calls.

This is a example why sometimes working with "copy" isn't necessarily a lost of performances.