Why urllib.urlopen.read() does not correspond to source code?

Question

I\'m trying to fetch the following webpage:

import urllib
urllib.urlopen(\"http://www.gallimard-jeunesse.fr/searchjeunesse/advanced/(order)/author?catalog[0]         


        

Answer 1

you can use python Selenium to solved your issue. Here is a example code have a look.

from selenium import webdriverr
url = "http://www.gallimard-jeunesse.fr/searchjeunesse/advanced/(order)/author?catalog[0]=1&SearchAction=1"
browser = webdriver.Firefox()
browser.get(url)
sleep(10)
all_body_id_html =  browser.find_element_by_id('body') # you can also get all html

Then due your rest of work according to your choice some more example with browser instance

def login(user='ssdf', password="cisin123"):
content = browser.find_element_by_id('content')
content.find_element_by_xpath('.//tbody/tr[2]//input[contains(@class,"textbox")]').send_keys(user)
content.find_element_by_xpath('.//tbody/tr[3]//input[contains(@class,"textbox")]').send_keys(password)
content.find_element_by_css_selector(".button").click()