Count how many values in a list that satisfy certain condition

Question

I have the following list,

mylist = [\'0.976850566018849\',
 \'1.01711066941038\',
 \'0.95545901267938\',
 \'1.13665822176679\',
 \'1.21770587184811\',
 \'1.         


        

Answer 1

I take compactness, you mentioned in the question, as shorter code. So, I present

sum(float(num) >= 1.3 for num in mylist)

This takes advantage of the fact that, in python True values are taken as 1 and False as 0. So, whenever float(num) >= 1.3 evaluates to Truthy, it will be 1 and if it fails, result would be 0. So, we add all the values together to get the total number of items which are greater than or equal to 1.3.

You can check that like this

True == 1
# True
True + True
# 2
False * 10
# 0