Python - get all combinations of a list

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[愿得一人]
[愿得一人] 2021-01-11 12:44

I know that I can use itertools.permutation to get all permutation of size r. But, for itertools.permutation([1,2,3,4],3) it will return (1,2,3) as

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  •  日久生厌
    2021-01-11 13:48

    It sounds like you are actually looking for itertools.combinations():

    >>> from itertools import combinations
    >>> list(combinations([1, 2, 3, 4], 3))
    [(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
    

    This example also shows how to convert the result to a regular list, just pass it to the built-in list() function.

    To get the combinations for each length you can just use a loop like the following:

    >>> data = [1, 2, 3, 4]
    >>> for i in range(1, len(data)+1):
    ...     print list(combinations(data, i))
    ... 
    [(1,), (2,), (3,), (4,)]
    [(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)]
    [(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)]
    [(1, 2, 3, 4)]
    

    Or to get the result as a nested list you can use a list comprehension:

    >>> [list(combinations(data, i)) for i in range(1, len(data)+1)]
    [[(1,), (2,), (3,), (4,)], [(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)], [(1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4)], [(1, 2, 3, 4)]]
    

    For a flat list instead of nested:

    >>> [c for i in range(1, len(data)+1) for c in combinations(data, i)]
    [(1,), (2,), (3,), (4,), (1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4), (1, 2, 3), (1, 2, 4), (1, 3, 4), (2, 3, 4), (1, 2, 3, 4)]
    

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