ffmpeg: Select frames at % position of video

Question

I\'m trying to create a 2x2 tile thumbnail of a video, that contains frames from 20%, 40%, 60%, and 80% through a video. I see that I need to use a video filter, with select

Answer 1

• Method 1: Frame intervals

  This may take some time depending on the input or return N/A for certain types of inputs (see the duration based method in this case).

  Get the total number of video frames:

  ffprobe  -select_streams v -show_entries stream=nb_frames -of default=nk=1:nw=1 -v quiet
  

  The command will output an integer value, for example:

  18034
  

  For the example above the frame interval is nb_frames / 5 = 18034 / 5 = 3607

  Finally the ffmpeg command is:

  ffmpeg -i  -filter:v "select=(gte(n\,3607))*not(mod(n\,3607)),tile=2x2" -frames:v 1 -vsync vfr -y tile.png
  

• Method 2: Duration intervals

  Same idea as above but use a duration in seconds. This can also take a while and the reported duration may be invalid (eg: if the file is truncated).

  ffprobe  -select_streams v -show_entries stream=duration -of default=nk=1:nw=1 -v quiet
  

  It returns a real value like:

  601.133333
  

  Your interval is 601 / 5 ~= 120 seconds:

  ffmpeg -i  -filter:v "select=(gte(t\,120))*(isnan(prev_selected_t)+gte(t-prev_selected_t\,120)),tile=2x2" -frames:v 1 -y tile.png
  

• Method 3: Seek & extract

  Seek to a specific time with -ss -i, extract a single frame and use imagemagick's montage to create the tile.

  Example output for a 10 minute countdown timer: